就算只有1%成功機率
我也要去試
沒有嘗試過才是最大的後悔
2015年7月21日 星期二
2014年12月8日 星期一
2014年7月25日 星期五
2014年2月14日 星期五
今天是希爾伯特的忌日
特此紀念
Hilbert's twenty-three problems are:
| Problem | Brief explanation | Status | Year Solved |
|---|---|---|---|
| 1st | The continuum hypothesis (that is, there is no set whose cardinality is strictly between that of the integers and that of the real numbers) | Resolved. Proven to be impossible to prove or disprove within the Zermelo–Fraenkel set theory with or without the Axiom of Choice (provided the Zermelo–Fraenkel set theory with or without the Axiom of Choice is consistent, i.e., contains no two theorems such that one is a negation of the other). There is general consensus that this solves the problem, although there have been proposals which would give a definitive truth value (see Ω-logic). | 1963 |
| 2nd | Prove that the axioms of arithmetic are consistent. | There is no consensus on whether results of Gödel and Gentzen give a solution to the problem as stated by Hilbert. Gödel'ssecond incompleteness theorem, proved in 1931, shows that no proof of its consistency can be carried out within arithmetic itself. Gentzen proved in 1936 that the consistency of arithmetic follows from the well-foundedness of the ordinal ε₀. | 1936? |
| 3rd | Given any two polyhedra of equal volume, is it always possible to cut the first into finitely many polyhedral pieces which can be reassembled to yield the second? | Resolved. Result: no, proved using Dehn invariants. | 1900 |
| 4th | Construct all metrics where lines are geodesics. | Too vague to be stated resolved or not.[n 1] | – |
| 5th | Are continuous groups automatically differential groups? | Resolved by Andrew Gleason, depending on how the original statement is interpreted. If, however, it is understood as an equivalent of the Hilbert–Smith conjecture, it is still unsolved. | 1953? |
| 6th | Mathematical treatment of the axioms of physics | Partially resolved depending on how the original statement is interpreted.[13] In particular, in a further explanation Hilbert proposed two specific problems: (i) axiomatic treatment of probability with limit theorems for foundation of statistical physics and (ii) the rigorous theory of limiting processes "which lead from the atomistic view to the laws of motion of continua". Kolmogorov’s axiomatics (1933) is now accepted as standard. There is some success on the way from the "atomistic view to the laws of motion of continua".[14] | 1933-2002? |
| 7th | Is a b transcendental, for algebraic a ≠ 0,1 and irrational algebraic b ? | Resolved. Result: yes, illustrated by Gelfond's theorem or the Gelfond–Schneider theorem. | 1935 |
| 8th | The Riemann hypothesis ("the real part of any non-trivial zero of the Riemann zeta function is ½") and other prime number problems, among them Goldbach's conjecture and the twin prime conjecture | Unresolved. | – |
| 9th | Find the most general law of the reciprocity theorem in any algebraic number field. | Partially resolved.[n 2] | – |
| 10th | Find an algorithm to determine whether a given polynomial Diophantine equation with integer coefficients has an integer solution. | Resolved. Result: impossible, Matiyasevich's theorem implies that there is no such algorithm. | 1970 |
| 11th | Solving quadratic forms with algebraic numerical coefficients. | Partially resolved.[citation needed] | – |
| 12th | Extend the Kronecker–Weber theorem on abelian extensions of the rational numbers to any base number field. | Unresolved. | – |
| 13th | Solve 7-th degree equation using continuous functions of two parameters. | The problem was partially solved by Vladimir Arnold based on work by Andrei Kolmogorov. [n 4] | 1957 |
| 14th | Is the ring of invariants of an algebraic group acting on a polynomial ring always finitely generated? | Resolved. Result: no, counterexample was constructed by Masayoshi Nagata. | 1959 |
| 15th | Rigorous foundation of Schubert's enumerative calculus. | Partially resolved.[citation needed] | – |
| 16th | Describe relative positions of ovals originating from a real algebraic curve and as limit cycles of a polynomial vector field on the plane. | Unresolved. | – |
| 17th | Express a nonnegative rational function as quotient of sums of squares. | Resolved. Result: yes, due to Emil Artin. Moreover, an upper limit was established for the number of square terms necessary.[citation needed] | 1927 |
| 18th | (a) Is there a polyhedron which admits only an anisohedral tiling in three dimensions? (b) What is the densest sphere packing? | (a) Resolved. Result: yes (by Karl Reinhardt). (b) Widely believed to be resolved, by computer-assisted proof (by Thomas Callister Hales). Result: Highest density achieved by close packings, each with density approximately 74%, such as cubic close packing and hexagonal close packing.[n 5][citation needed] | (a) 1928 (b) 1998 |
| 19th | Are the solutions of regular problems in the calculus of variations always necessarily analytic? | Resolved. Result: yes, proven by Ennio de Giorgi and, independently and using different methods, by John Forbes Nash. | 1957 |
| 20th | Do all variational problems with certain boundary conditions have solutions? | Resolved. A significant topic of research throughout the 20th century, culminating in solutions[citation needed] for the non-linear case. | ? |
| 21st | Proof of the existence of linear differential equations having a prescribed monodromic group | Resolved. Result: Yes or no, depending on more exact formulations of the problem.[citation needed] | ? |
| 22nd | Uniformization of analytic relations by means of automorphic functions | Resolved.[citation needed] | ? |
| 23rd | Further development of the calculus of variations | Unresolved. | – |
2014年2月1日 星期六
2014年1月14日 星期二
2014年1月13日 星期一
Paul Mccartney
Maybe I'm Amazed
Baby I'm amazed at the way you love me all the time
Maybe I'm afraid of the way I love you
Baby I'm amazed at the the way you pulled me out of time
Hung me on a line
Maybe I'm amazed at the way I really need you
Baby I'm a man and maybe I'm a lonely man
Who's in the middle of something
That he dosen't really understand
Babe I'm a man and maybe you're the only woman
Who could ever help me
Baby won't you help to me understand
Baby I'm a man and maybe I'm a lonely man
Who's in the middle of something
That he dosen't really understand
Babe I'm a man and maybe you're the only woman
Who could ever help me
Baby won't you help me understand
Baby I'm amazed at the way you're with me all the time
Maybe I'm afraid of the way I leave you
Baby I'm amazed at the way you help me sing my song
You right me when I'm wrong
Maybe I'm amazed at the way I really need you
Baby I'm amazed at the way you love me all the time
Maybe I'm afraid of the way I love you
Baby I'm amazed at the the way you pulled me out of time
Hung me on a line
Maybe I'm amazed at the way I really need you
Baby I'm a man and maybe I'm a lonely man
Who's in the middle of something
That he dosen't really understand
Babe I'm a man and maybe you're the only woman
Who could ever help me
Baby won't you help to me understand
Baby I'm a man and maybe I'm a lonely man
Who's in the middle of something
That he dosen't really understand
Babe I'm a man and maybe you're the only woman
Who could ever help me
Baby won't you help me understand
Baby I'm amazed at the way you're with me all the time
Maybe I'm afraid of the way I leave you
Baby I'm amazed at the way you help me sing my song
You right me when I'm wrong
Maybe I'm amazed at the way I really need you
2014年1月10日 星期五
2013年12月27日 星期五
2013年10月26日 星期六
2013年10月12日 星期六
2013年9月22日 星期日
原來我比較像TS阿，比較喜歡AJ說...
Full personality description:
You're often found diving into a book or spending hours working on that project of yours. It's important that you put in as much of an effort learning as possible so your knowledge will someday come in handy. Because of this, you may sometimes be skeptical of things that you don't have any proof of.
While you tend to be booksmart as opposed to streetsmart, you also tend to be a tad socially awkward, not always sure how well you fit in with your friends or maybe not even having a lot of them in the first place, but you're still a solid friend when it comes down to it and would be there to help any of them with their problems.
Even though you may be talented, you're the total opposite of a showoff, shying away from bragging or even talking about your talents. You don't want the world to think you're a braggart, after all. You're quite humble and modest, but you're also looking for acceptance and praise for your talents.
- See more at: http://www.bronyland.com/pony-personality-test/?q=OTAzMXw4MTUxMTQ#sthash.ur8O4hVC.dpuf2013年9月2日 星期一
2013年8月28日 星期三
Linkin Park I'll be gone
Like shining oil, this night is dripping down
Stars are slipping down, glistening
And I'm trying not to think what I'm leaving now
No deceiving now, it's time you let me know.
Let me know
When the lights go out and we open our eyes,
Out there in the silence, I'll be gone, I'll be gone.
Let the sun fade out and another one rise
Climbing through tomorrow, I'll be gone, I'll be gone.
This air between us is getting thinner now
Into winter now. Bitter sweet
And 'cross that horizon this sun is setting down
You're forgetting now, it's time you let me go, let me go
When the lights go out and we open our eyes,
Out there in the silence, I'll be gone, I'll be gone.
Let the sun fade out and another one rise
Climbing through tomorrow, I'll be gone, I'll be gone.
And tell them I couldn't tell myself
And tell them I was alone
Oh, tell me I am the only one
And there's nothing that can stop me.
When the lights go out and we open our eyes,
Out there in the silence, I'll be gone, I'll be gone.
Let the sun fade out and another one rise
Climbing through tomorrow, I'll be gone, I'll be gone, I'll be gone.
Stars are slipping down, glistening
And I'm trying not to think what I'm leaving now
No deceiving now, it's time you let me know.
Let me know
When the lights go out and we open our eyes,
Out there in the silence, I'll be gone, I'll be gone.
Let the sun fade out and another one rise
Climbing through tomorrow, I'll be gone, I'll be gone.
This air between us is getting thinner now
Into winter now. Bitter sweet
And 'cross that horizon this sun is setting down
You're forgetting now, it's time you let me go, let me go
When the lights go out and we open our eyes,
Out there in the silence, I'll be gone, I'll be gone.
Let the sun fade out and another one rise
Climbing through tomorrow, I'll be gone, I'll be gone.
And tell them I couldn't tell myself
And tell them I was alone
Oh, tell me I am the only one
And there's nothing that can stop me.
When the lights go out and we open our eyes,
Out there in the silence, I'll be gone, I'll be gone.
Let the sun fade out and another one rise
Climbing through tomorrow, I'll be gone, I'll be gone, I'll be gone.
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